We were given two handouts: ACID/BASE PROPERTIES LAB
We were going over two example problems
- Video on this is going to be posted (5:00 pm or later) to help you prepare for the QUIZ TOMORROW!
Notes (just in case the video fails):
- LeChatelier's Principle
- Ksp
- Calculate [ ] at equilibrium
- Calculate Ksp (using solubility)
- Calculate S (solubility)
- have to be given Ksp
- Need number of ions and memorize algorithms
- Ksp - Common Ion Problems
- Solubility and Ksp Problems
- Ex 1: Which of the following has the lowest solubility?
- a.) AgC2H3O2 Ksp= = 1.9 x 10 ^-3
- b.) AgCl Ksp = 1.8 x 10 ^ -10
- c.) BaCrO4 Ksp = 1.2 x 10^ -10 (Ksp smaller, so lowest solubility)
2 ions : AgC2H3O2 (s) -------> Ag+ (aq) + C2H3O2 - (aq)
....so on for the next two dissociations...
all have two ions!
- Ex 2: Which of the following has the lowest solubility?
- a.) MgCO3 Ksp = 6.8 x 10 ^-6
- b.) PbCl2 Ksp = 1.7 x 10^-5
- c.) Al(OH)3 Ksp = 2.0 x 10^-31 (SMALLEST Ksp)
write out the dissociations....
1st (a.) one has two ions, so take the square root of Ksp.
2nd (b.) one has 3 ions! Take the cube root of that Ksp/4.
3rd (c.) one has 4 ions! Take fourth root of Ksp/27.
- Common Ion Problem
- What is the solubility of PbCl2 in 0.100M MgCl2? The Ksp of PbCl2 = 1.7 x 10^-5
- Dissociation equation: MgCl2 ----> Mg 2+ (aq) + 2Cl- (aq)
- MgCl2 = 0.100M. and Mg= 0.100M. and Cl= 0.200M.
- PbCl2 <-----> Pb2+ (aq) + 2 Cl- (aq)
- I 0 0.2
- C +x +2x
- E (x) (0.200+2x)
- Use ice for PbCl2
- 1.7x10^-5 = (x)(0.200+2x)^2 , Get rid of the small x; (2x)
- 1.7x10^-5 = (x)(0.200)^2
- 1.7x10^-5 = 0.04x
- x = solubility = 4.25 x 10^-4
HOMEWORK: STUDY!
NEXT BLOGGER WILL BE: EJ REYNOLDS
NEXT BLOGGER WILL BE: EJ REYNOLDS
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